MATH SOLVE

4 months ago

Q:
# Dianna has 4 quarters, 3 dimes, and 3 nickels in her purse. She reaches into her purse and randomly grabs two coins, one at a time. What is the probability of first picking a dime and then, without replacing it, selecting a nickel?

Accepted Solution

A:

At the beginning there are 3 dimes out of 10 coins:

P(first coin is a dime) = 3/10

After that there are 3 nickels out of 9 remaining coins:

P(second coin is a nickel) = 3/9 = 1/3

P(dime, then nickel) = P(first coin is a dime) x P(second coin is a nickel)

= 3/10 x 1/3

= 1/10

Answer:

1/10 . if im wrong im sorry

P(first coin is a dime) = 3/10

After that there are 3 nickels out of 9 remaining coins:

P(second coin is a nickel) = 3/9 = 1/3

P(dime, then nickel) = P(first coin is a dime) x P(second coin is a nickel)

= 3/10 x 1/3

= 1/10

Answer:

1/10 . if im wrong im sorry