MATH SOLVE

2 months ago

Q:
# A dog is attached to a 49 foot rope fastened to the outside corner of a fenced-in garden that measures 42 feet by 51 feet. Assuming that the dog cannot enter the garden, compute the exact area that the dog can wander.

Accepted Solution

A:

Assuming that the corner of the fence has right angle, the the area that the dog wandered will be given by:

A=θ/360πr²

Where:

θ=360-90=270°

r=49 ft

hence the area will be:

A=270/360×π×49²

A=5657.23 ft²

Thus the dog will wander in the area of 5657.23 ft²

A=θ/360πr²

Where:

θ=360-90=270°

r=49 ft

hence the area will be:

A=270/360×π×49²

A=5657.23 ft²

Thus the dog will wander in the area of 5657.23 ft²